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Author Question: Given the following free energies of formation:GfC2H2(g)209.2 kJ/molC2H6(g)32.92 kJ/molcalculate Kp ... (Read 97 times)

V@ndy87

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on: Mar 21, 2021

Question 1

Given the following data, calculate the normal boiling point for formic acid (HCOOH).
 
ΔHf°(kJ/mol)
S°(J/mol K)
HCOOH(l)
-410.
130.0
HCOOH(g)
-363
251.0
 


◦ 0.39 °C
◦ 388 °C
◦ 661 °C
◦ 279 °C
◦ 115 °C

Question 2

Given the following free energies of formation:
 
ΔGf°
C2H2(g)
209.2 kJ/mol
C2H6(g)
–32.92 kJ/mol
calculate Kp at 298 K for C2H2(g) + 2H2(g) C2H6(g)


◦ 97.7
◦ 1.10
◦ 7.95 × 1030
◦ 2.76 × 1042
◦ None of these is within a factor of 10 of the correct answer.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by V@ndy87 on Mar 21, 2021

nekcihc358

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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V@ndy87

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)

mcabuhat

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Reply 3 on: Yesterday
Wow, this really help

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