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Author Question: The equilibrium constant K for the dissociation reaction of a molecule X2 X2(g) 2X(g)was measured ... (Read 34 times)

audie

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on: Mar 21, 2021
The equilibrium constant K for the dissociation reaction of a molecule X2

    X2(g) 2X(g)

was measured as a function of temperature (in K). A graph of ln K versus 1/T for this reaction gives a straight line with a slope of –1.352 104 and an intercept of 18.35 K. The value of ΔS for this dissociation reaction is:


◦ 2.207 J/K·mol
◦ 305.1 J/K·mol
◦ 152.6 J/K·mol
◦ 76.28 J/K·mol
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by audie on Mar 21, 2021

wshriver

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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audie

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Reply 2 on: Mar 21, 2021
YES! Correct, THANKS for helping me on my review

bulacsom

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Reply 3 on: Yesterday
Excellent

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