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Author Question: The complex ions of Zn2+ are all colorless. The most likely explanation for this is: (Read 126 times)

chandani

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on: Mar 21, 2021

Question 1

The complex ion NiCl42– is tetrahedral. The number of unpaired electrons in the complex is:

◦ 0
◦ 1
◦ 2
◦ 3
◦ 4

Question 2

The complex ions of Zn2+ are all colorless. The most likely explanation for this is:

◦ Zn2+ is paramagnetic.
◦ Zn2+ exhibits “d orbital” splittings in its complexes such that they absorb all wavelengths in the visible region.
◦ Since Zn2+ is a d10 ion, it does not absorb visible light even though the “d orbital” splittings are correct for absorbing visible wavelengths.
◦ Zn2+ is not a transition metal ion.
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by chandani on Mar 21, 2021

kjohnson

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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chandani

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)

olderstudent

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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