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Author Question: Describe the graph of the equation x2 + y2 = 3. (Read 119 times)

tth

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  • Posts: 579
on: May 26, 2021

Question 1

A particle starts at A (4, -6) and its coordinates change by  △x = -1  and  △y = 2.  Find its new position.
◦ (3, -8)
◦ (4, -8)
◦ (3, -4)
◦ (5, -4)
◦ (5, -8)

Question 2

Describe the graph of the equation  x2 + y2 = 3.
◦ line passing through the point (0, 3)
◦ circle centred at the origin with radius 9
◦ line passing through the point (3, 0)
◦ circle centred at the origin with radius
◦ circle centred at the origin with radius 3
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Marked as best answer by tth on May 26, 2021

Liamb2179

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tth

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Reply 2 on: May 26, 2021
Thanks for the timely response, appreciate it

deja

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Reply 3 on: Yesterday
Gracias!

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