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Author Question: Find the points of intersection of the pairs of curves y = x2 - 4 and y = 2x -1. (Read 104 times)

lilldybug07

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on: May 26, 2021

Question 1

Write an equation for the graph obtained by shifting the graph of  y = (x - 3)2 - 1 up 2 units and right 2 units.
◦ y = (x - 1)2 + 1
◦ y = (x - 1)2 - 3
◦ y = (x - 3)2 + 1
◦ y = (x - 5)2 + 1
◦ y = (x - 5)2 - 3

Question 2

Find the points of intersection of the pairs of curves  y = x2 - 4 and  y = 2x -1.
◦ (-1,-3)
◦ (-1,-3)  and  (3, 5)
◦ (3, 5)
◦ (-1,-3),  (0, -1),  and  (3, 5)
◦ These curves do not intersect.
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Marked as best answer by lilldybug07 on May 26, 2021

billybob123

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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lilldybug07

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Reply 2 on: May 26, 2021
Thanks for the timely response, appreciate it

diana chang

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Reply 3 on: Yesterday
Wow, this really help

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