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Author Question: Write an equality that describes the exterior of the circle with centre (3, - 5) and radius 6. (Read 103 times)

asan beg

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on: May 26, 2021

Question 1

Write an equation for the graph obtained by shifting the graph of the equation   down 1 unit and left 1 unit.
◦ y = (x - 1)2 - 3
◦ y = (x - 1)2 + 5
◦ y = (x - 1)2 + 3
◦ y = (x - 3)2 + 5
◦ y = (x + 1)2 + 3

Question 2

Write an equality that describes the exterior of the circle with centre (3, - 5) and radius 6.
◦ (x + 3)2 + (y - 5)2  > 6
◦ (x - 3)2 + (y + 5)2  > 36
◦ (x - 3)2 + (y - 5)2  > 36
◦ (x - 3)2 + (y + 5)2  > 6
◦ (x + 3)2 + (y - 5)2  > 36
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Marked as best answer by asan beg on May 26, 2021

juiceman1987

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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asan beg

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Reply 2 on: May 26, 2021
Gracias!

okolip

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Reply 3 on: Yesterday
:D TYSM

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