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Author Question: Find the second derivative of the function f(x) = x3 sin(2x). (Read 110 times)

Caiter2013

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on: May 26, 2021

Question 1

Find the second derivative of the function  f(x) =  .
◦ - - +
◦ + +
◦ - + +
◦ + -
◦ - + -

Question 2

Find the second derivative of the function  f(x) = x3 sin(2x).
◦ 6x sin(2x) + 12x2 cos(2x) - 4x3 sin(2x)
◦ - 6x sin(2x) + 12x2 cos(2x) + 4x3 sin(2x)
◦ 6x sin(2x) + 8x2 cos(2x) - 4x3 sin(2x)
◦ - 6x sin(2x) + 8x2 cos(2x) - 4x3 sin(2x)
◦ 6x sin(2x) + 12x2 cos(2x) + 4x3 sin(2x)
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Marked as best answer by Caiter2013 on May 26, 2021

Bison

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Caiter2013

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Reply 2 on: May 26, 2021
Great answer, keep it coming :)

nyrave

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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