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Author Question: Find an equation of the line tangent to the curve e1/y - ey = 2x at the point (0,1). (Read 115 times)

JMatthes

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on: May 26, 2021

Question 1

The acceleration of an object moving on the x-axis is 9e3t.  Find the velocity v if the velocity at time t = 0 is 4 units per second.
◦ v = 3e3t + 1
◦ v = 27e3t - 23
◦ v = e3t + 3
◦ v = 9e3t - 5
◦ v = + 1

Question 2

Find an equation of the line tangent to the curve  e1/y - ey = 2x  at the point (0,1).
◦ y = -1 +
◦ y = -
◦ y = 1 -
◦ y = -
◦ y = 1 +
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Marked as best answer by JMatthes on May 26, 2021

bubulittle310@msn.cn

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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JMatthes

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Reply 2 on: May 26, 2021
Wow, this really help

T4T

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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