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Author Question: Find an approximation for the area under the curve y = 1 - x2 and above the x-axis from x = 0 to x = ... (Read 60 times)

APUS57

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on: May 26, 2021
Find an approximation for the area under the curve  y = 1 - x2  and above the x-axis from  x =  0  to  
x = 1  using a sum of areas of four  rectangles each having width  1/4  and  (a) tops lying under the curve,  or  (b) tops lying above the curve.  What does this tell you about the actual area under the curve?
◦ (a)  ,   (b)   ;    <  area under curve  <  
◦ (a)  ,   (b)   ;    <  area under curve  <  
◦ (a)  ,   (b)   ;    <  area under curve  <  
◦ (a)  ,   (b)   ;    <  area under curve  <  
◦ (a)  ,   (b)   ;    <  area under curve  <  
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Marked as best answer by APUS57 on May 26, 2021

connor417

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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APUS57

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Reply 2 on: May 26, 2021
YES! Correct, THANKS for helping me on my review

mjenn52

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Reply 3 on: Yesterday
:D TYSM

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