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Author Question: Construct and simplify a sum approximating the area above the x-axis and under the curve y = x2 ... (Read 21 times)

jenna1

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on: May 26, 2021

Question 1

Given that the area under the curve  y = x2  and above the x-axis from  x = 0  to  x = a > 0  is   square units, find the area under the same curve from  x = -2  to  x = 3.
◦  square units
◦
◦ 9  square units
◦  square units
◦ 6  square units

Question 2

Construct  and simplify a sum approximating the area above the x-axis and under the curve  y = x2  between x = 0  and  x = 3  by using  n  rectangles having equal widths  and tops lying under or on the curve.  Find the actual area as a suitable limit.
◦ ,  area = 9 square units
◦ ,  area = 9 square units
◦ ,  area = 9 square units
◦ ,  area = 6 square units
◦ ,  area = 6 square units
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Marked as best answer by jenna1 on May 26, 2021

blfontai

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jenna1

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Reply 2 on: May 26, 2021
YES! Correct, THANKS for helping me on my review

miss_1456@hotmail.com

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Reply 3 on: Yesterday
Wow, this really help

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