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Author Question: Evaluate the integral sin 4x dx. (Read 41 times)

ereecah

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on: May 26, 2021

Question 1

Evaluate the integral sin 2θ dθ.
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Question 2

Evaluate the integral sin 4x dx.
◦ (4 sin 4x + 3 cos 4x) + C
◦ (3 sin 4x - 4 cos 4x) + C
◦ (4 sin 4x - 3 cos 4x) + C
◦ (3 sin 4x + 4 cos 4x) + C
◦ (3 sin 4x - 4 cos 4x) + C
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Marked as best answer by ereecah on May 26, 2021

voltaire123

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ereecah

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Reply 2 on: May 26, 2021
YES! Correct, THANKS for helping me on my review

alexanderhamilton

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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