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Author Question: Let f(x) = e-x2 and let I = dx. Given that 12 for 0 x 1, what is the smallest value of n for ... (Read 32 times)

tfester

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on: May 26, 2021
Let  f(x) = e-x2 and let  I = dx. Given that ≤ 12 for 0 ≤  x ≤ 1,  what is the smallest value of  n  for which the Simpson's Rule approximation  I  ≈  S2n  will have error  less than 0.0005 in absolute value?  Hence, what is the value of  I  rounded to 3 decimal places?
◦ n = 4,  I  ≈  S8  ≈  0.747
◦ n = 2,  I  ≈  S4  ≈  0.747
◦ n = 3,  I  ≈  S6  ≈  0.747
◦ n = 1,  I  ≈  S2  ≈  0.747
◦ n = 3,  I  ≈  S8  ≈  0.747
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Marked as best answer by tfester on May 26, 2021

6ana001

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tfester

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Reply 2 on: May 26, 2021
Thanks for the timely response, appreciate it

at

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Reply 3 on: Yesterday
:D TYSM

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