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Author Question: Where does the curve x = 2t2 - 5, y = t3 + t have a tangent line that is perpendicular to the line ? (Read 67 times)

EY67

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on: May 26, 2021

Question 1

Find the slopes of two lines tangent to the parametric curve x = t3 + t2 - 6t + 1, y = t2 + t  - 4 at the point (1, 2) on the curve.
◦ ,  -
◦ -6, -
◦ 2, -3
◦ - ,  
◦ - ,

Question 2

Where does the curve  x = 2t2 - 5,  y = t3 + t  have a tangent line that is perpendicular to the line  ?
◦  and  (3, -2)
◦  and  (-3, -2)
◦  and  (-3, 2)
◦  and  (-3, 2)
◦   and  (3, -2)
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Marked as best answer by EY67 on May 26, 2021

ilianabrrr

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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EY67

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Reply 2 on: May 26, 2021
Wow, this really help

DylanD1323

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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