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Author Question: Find the area of the surface generated by rotating the lemniscate r2 = a2 cos(2) about the line = 0. (Read 72 times)

corkyiscool3328

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on: May 26, 2021

Question 1

Find the surface area generated by  revolving the arc of  r = a(1 - cosθ), 0 ≤ θ ≤ π  about the line θ = 0.
◦  square units
◦  square units
◦  square units
◦  square units
◦  square units

Question 2

Find the area of the surface generated by rotating the lemniscate  r2 = a2 cos(2θ)  about the line  θ = 0.
◦ π a2  square units
◦ 2 π a2  square units
◦ 2 π a2  square units
◦ 4 π a2  square units
◦ 4 π a2  square units
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Marked as best answer by corkyiscool3328 on May 26, 2021

vickybb89

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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corkyiscool3328

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Reply 2 on: May 26, 2021
:D TYSM

carlsona147

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Reply 3 on: Yesterday
Gracias!

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