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Author Question: Find an equation of the line tangent to the parametric space curve r(t) = (t2 + 3t + 1) i + (2 - 7t ... (Read 95 times)

Haya94

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on: May 27, 2021
Find an equation of the line tangent to the parametric space curve
 r(t) = (t2 + 3t + 1) i + (2 - 7t j + (4sin(t)  -3)k  at the point on the curve corresponding to t = 0.
◦ r(u) = (1 + 3u) i + (2 - 7u) j + (- 3 + 4s) k,  u ∈  R
◦ x + 2y - 3z - 14 = 0
◦ x + y + z = 0
◦ 3x - 7y + 4z -23 = 0
◦ r(u) = (3 + u) i + (-7 + 2u) j + (4 - 3u) k, u ∈  R
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Marked as best answer by Haya94 on May 27, 2021

Missbam101

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Haya94

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Reply 2 on: May 27, 2021
Great answer, keep it coming :)

chjcharjto14

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Reply 3 on: Yesterday
Wow, this really help

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