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Author Question: An object is moving to the right in the xy-plane along the curve y = x2. At the instant when it is ... (Read 35 times)

robinn137

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on: May 27, 2021

Question 1

The position vector of a moving particle in space is given by the vector equation . When will the speed of the particle be 4 units?
◦ t = 0
◦ t = 6  and t = - 2
◦ t = 6
◦ t = 2
◦ t = - 6  and  t = 2

Question 2

An object is moving to the right in the xy-plane along the curve  y = x2.  At the instant when it is at the point  ,  its speed is  2  and that speed is decreasing at rate  1.  What are the velocity and acceleration of the object at that instant?
◦ v =  (i + j),   a =  -i + j
◦ v = (i + j),   a =  (1 + ) i + (1 - ) j
◦ v =  2 (i + j),   a =  -i + j
◦ v = 2 (i + j),   a =  (1 + ) i + (1 - ) j
◦ v = (i + j),   a = i - j
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Marked as best answer by robinn137 on May 27, 2021

makaylafy

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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robinn137

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Reply 2 on: May 27, 2021
YES! Correct, THANKS for helping me on my review

ghepp

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Reply 3 on: Yesterday
Wow, this really help

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