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Author Question: The equation x + y2 + sin(xy) = 1 defines y as a function of x near the point (0, 1). Find the value ... (Read 61 times)

Diane

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on: May 27, 2021

Question 1

Near what points can the equation  2x2 + xy + y2 = 7  not be solved for  y  as a function of  x?
◦ (2, 1) and (2, -1)
◦ (2, -1) and (-2, 1)
◦ (2, 1), (-2, -1), (2, -1), and (-2, 1)
◦ (2, -1), (-2, 1), and (0, 0)
◦ (2, 1) and (-2, -1)

Question 2

The equation  x + y2 + sin(xy) = 1  defines  y  as a function of  x  near the point  (0, 1).  Find the value of  at that point.
◦ -2
◦ -1
◦ 1
◦ 0
◦ 2
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Marked as best answer by Diane on May 27, 2021

ghepp

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Diane

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Reply 2 on: May 27, 2021
Excellent

Kedrick2014

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Reply 3 on: Yesterday
Gracias!

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