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Author Question: Find the maximum and minimum values of the function f(x, y, z) = 3x2 + 3y2 + 5z2 + 2xy - 2xz - 2yz ... (Read 102 times)

newyorker26

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on: May 27, 2021
Find the maximum and minimum values of the function f(x, y, z) = 3x2 + 3y2 + 5z2 + 2xy - 2xz - 2yz  over the sphere x2 + y2 + z2 = 6.
◦ maximum value  24, minimum value  16
◦ maximum value  36, minimum value  18
◦ maximum value  20, minimum value  18
◦ maximum value  36, minimum value  12
◦ maximum value  18, minimum value  12
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Marked as best answer by newyorker26 on May 27, 2021

phuda

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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newyorker26

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Reply 2 on: May 27, 2021
Great answer, keep it coming :)

fatboyy09

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Reply 3 on: Yesterday
Gracias!

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