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Author Question: Compute div F for F = sin 2x, cos 2y, tan 2z. (Read 23 times)

jhjkgdfhk

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on: May 27, 2021

Question 1

Let  φ = arctan(x) - arctan(z) and  ψ = . Find a simplified expression for  grad(φ) × grad(ψ).
◦  j
◦  j
◦ -  j
◦ 0  (zero vector field)
◦ 0  (zero scalar field)

Question 2

Compute div F  for  F =  sin 2x, cos 2y, tan 2z.
◦ 2cos 2x - 2sin 2y + 2sec2 z
◦ -cos 2x + sin 2y + 2sec2 z
◦ 2cos 2x + 2sin 2y + 2sec2 z
◦ 2cos 2x - 2sin 2y + 2sec z
◦ cos 2x + sin 2y + 2sec2 z
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Marked as best answer by jhjkgdfhk on May 27, 2021

bulacsom

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jhjkgdfhk

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Reply 2 on: May 27, 2021
Wow, this really help

cdmart10

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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