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Author Question: You probably know by now that a differential k-form k 1 on a domain D Rn is very similar to a ... (Read 34 times)

mckennatimberlake

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on: May 27, 2021
You probably know by now that a differential k-form  k ≥  1 on a domain D ⊂ Rn is very similar to a vector field on D, and hence a correspondence between the two may be established.
Let  Φ  = F dx + G dy + H dz  be a differential 1-form on a domain D ⊂ R3 and let   be the vector field corresponding to Φ. Using this set up, find the vector differential identity corresponding to the fact d2Φ = .
◦ ∇(divF) = 0
◦ curl(curl F) = 0
◦ div(curl F) = 0
◦ ∇2F = 0
◦ curl(F) = 0
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Marked as best answer by mckennatimberlake on May 27, 2021

jsm54321

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mckennatimberlake

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Reply 2 on: May 27, 2021
:D TYSM

lindahyatt42

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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