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Author Question: Find the solution of the differential equation = 12 - 2x + 1 that satisfies y(1) = 3. (Read 119 times)

ahriuashd

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on: May 27, 2021

Question 1

Find the function satisfying F'(x) = x e-x,   F(0) = 1.
◦ F(x) = -1 - e-x(x + 1)
◦ F(x) = 3 - e-x(x + 1)
◦ F(x) = 1 - e-x(x - 1)
◦ F(x) = 2 + e-x(x - 1)
◦ F(x) = 2 - e-x(x + 1)

Question 2

Find the solution of  the differential equation   = 12 - 2x + 1 that satisfies y(1) = 3.
◦ y = - 2
◦ 8x3/2 - x2 + x
◦ 8x - x2 + x + C
◦ 8x - x2 + x - 5
◦ 8x3 - x2 + x + 5
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Marked as best answer by ahriuashd on May 27, 2021

yeungji

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ahriuashd

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Reply 2 on: May 27, 2021
:D TYSM

olderstudent

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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