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Author Question: Determine a multiplier (integrating factor) of the first order linear differential equation (Read 86 times)

Evvie72

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on: May 27, 2021

Question 1

The change of dependent variable y =  transforms the equation  x + y = xy2cos(x) into
◦ + = cos(x)
◦ + =
◦ - = -cos(x)
◦ ln(v) + =
◦ - = cos(x)

Question 2

Determine a multiplier (integrating factor) of the first order linear differential equation
◦ μ(x) = -
◦ μ(x) =
◦ μ(x) = e2/x
◦ μ(x) = e-2/x
◦ μ(x) = -
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Marked as best answer by Evvie72 on May 27, 2021

alexisweber49

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Evvie72

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  • Posts: 519
Reply 2 on: May 27, 2021
YES! Correct, THANKS for helping me on my review

bimper21

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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