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Author Question: The correct answer for the addition of 7.5 g + 2.26 g + 1.311 g + 2 g is ________. (Read 113 times)

wrbasek0

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  • Posts: 560
on: Jun 7, 2021

Question 1

What is the answer, with the correct number of decimal places, for this problem?

4.392 g + 102.40 g + 2.51 g =

◦ 109.30 g
◦ 109 g
◦ 110 g
◦ 109.3 g
◦ 109.302 g

Question 2

The correct answer for the addition of 7.5 g + 2.26 g + 1.311 g + 2 g is ________.
◦ 10 g
◦ 13.0 g
◦ 13.071 g
◦ 13.1 g
◦ 13 g
Chemistry: An Introduction to General, Organic, and Biological Chemistry ¦ Timberlake ¦ 13th Edition
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Marked as best answer by wrbasek0 on Jun 7, 2021

GCabra

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Reply #1 on: Jun 7, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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wrbasek0

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  • Posts: 560
Reply 2 on: Jun 7, 2021
Thanks for the timely response, appreciate it

juliaf

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  • Posts: 344
Reply 3 on: Yesterday
Great answer, keep it coming :)

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