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Author Question: The first derivative is to instantaneous velocity as the second derivative is to. (Read 102 times)

corkyiscool3328

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on: Jun 16, 2021

Question 1

Suppose that y is a function of u, and that u is itself a function of x. How does one find the derivative of y in terms of x?
◦ The difference rule:  =  - 
◦ The chain rule:  =  ∙ 
◦ The product rule:  = y ∙  + u ∙ 
◦ The sum rule:  =  + 

Question 2

The first derivative is to instantaneous velocity as the second derivative is to .
◦ Instantaneous acceleration
◦ Average momentum
◦ Instantaneous speed
◦ Average velocity
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by corkyiscool3328 on Jun 16, 2021

Bison

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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corkyiscool3328

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Reply 2 on: Jun 16, 2021
:D TYSM

alexanderhamilton

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Reply 3 on: Yesterday
Wow, this really help

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