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Author Question: Use a graphing calculator to find the approximate location of all relative extrema.f(x) = 0.1x5+ ... (Read 25 times)

abc

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on: Jun 16, 2021
Use a graphing calculator to find the approximate location of all relative extrema.

f(x) = 0.1x5 + 5x4 - 8x3 - 15x2 - 6x - 46
◦ Relative maxima at x = -41.036 and x = -0.193; relative minima at x = -0.61 and x=  2.015
◦ Relative maxima at x = -41.159 and x = -0.186; relative minima at x = -0.548 and x = 1.979
◦ Relative maxima at x = -41.132 and x = -0.273; relative minima at x = -0.547 and x = 1.952
◦ Relative maxima at x = -41.212 and x = -0.219; relative minima at x = -0.593 and x = 2.006
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by abc on Jun 16, 2021

zenzy

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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abc

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Reply 2 on: Jun 16, 2021
Great answer, keep it coming :)

miss.ashley

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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