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Author Question: Suppose that the daily cost, in dollars, of producing x televisions isC(x) = 0.003x3+ 0.1x2+ 68x + ... (Read 85 times)

jerry coleman

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Suppose that the daily cost, in dollars, of producing x televisions is 
C(x) = 0.003x3 + 0.1x2 + 68x + 620, 
and currently 60 televisions are produced daily.  Use C(60) and the marginal cost to estimate the daily cost of increasing production to 63 televisions daily. Round to the nearest dollar.
◦ $5978
◦ $6051
◦ $5841
◦ $6045


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Marked as best answer by jerry coleman on Jun 16, 2021

dyrone

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jerry coleman

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Reply 2 on: Jun 16, 2021
YES! Correct, THANKS for helping me on my review


ashely1112

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Reply 3 on: Yesterday
Gracias!

 

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