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Author Question: Given that A(x) = C(x)/x , where A(x) is the average-cost function and C(x) is the total-cost ... (Read 75 times)

michelleunicorn

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Given that A(x) = C(x)/x , where A(x) is the average-cost function and C(x) is the total-cost function, find an expression for A'(x) and solve the equation A'(x) = 0 to find the minimum average cost.
◦ A'(x) =  = 0  ⇒  xC(x) - C'(x) = 0  ⇒   = A(x) = C(x)
◦ A'(x) =  = 0  ⇒  xC'(x) - C(x) = 0  ⇒   = A(x) = C'(x)
◦ A'(x) =  = 0  ⇒  xC(x) - C'(x) = 0  ⇒   = A(x) = 
◦ A'(x) =  = 0  ⇒ xC(x) - C'(x) = 0  ⇒   = A(x) = 


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Marked as best answer by michelleunicorn on Jun 16, 2021

Christopher

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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michelleunicorn

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Reply 2 on: Jun 16, 2021
:D TYSM


Dinolord

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Reply 3 on: Yesterday
Wow, this really help

 

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