Use calculus to find any critical points and inflection points of ...

[eruditmonkey@yahoo.com]

Use calculus to find any critical points and inflection points of the given function. Then determine the concavity of the function and the intervals over which it is increasing/decreasing.

f(x) =  e^(1/7)x
◦ Critical points: critical point at x = 0
Inflection points: none
Concavity: concave up for all real numbers 
Increasing: increasing for all x < 0 and decreasing for all x > 0
◦ Critical points: none
Inflection points: none
Concavity: concave up for all real numbers
Increasing: increasing for all real numbers
◦ Critical points: none
Inflection points: none
Concavity: concave down for all real numbers
Increasing: increasing for all real numbers
◦ Critical points: none
Inflection points: point of inflection at x = 0
Concavity: concave down for all x < 0 and concave up for all x > 0 
Increasing: increasing for all real numbers

[shewald78]

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

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[eruditmonkey@yahoo.com]

YES! Correct, THANKS for helping me on my review

[chereeb]

Thanks for the timely response, appreciate it