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Author Question: For the given function, find the requested relative extrema or extreme value.y = 6ex+ xex; relative extrema (Read 39 times)

nelaaney

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on: Jun 16, 2021

Question 1

For the given function, find the requested relative extrema or extreme value.

y = xe2x; relative extrema
◦ (1/2, e/2), relative minimum
◦ (- 1/2, - e/2), relative maximum
◦ (1/2, 1/(2e)), relative maximum
◦ (- 1/2, - 1/(2e)), relative minimum

Question 2

For the given function, find the requested relative extrema or extreme value.

y = 6ex + xex; relative extrema
◦ (6, 12e6), relative maximum
◦ (-6, 0), relative minimum
◦ (7, 13e7), relative maximum
◦ (-7, -e-7), relative minimum
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by nelaaney on Jun 16, 2021

phuda

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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nelaaney

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Reply 2 on: Jun 16, 2021
Great answer, keep it coming :)

tandmlomax84

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Reply 3 on: Yesterday
:D TYSM

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