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Author Question: The time to failure t, in hours, of a certain machine can often be assumed to be exponentially ... (Read 69 times)

jman1234

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on: Jun 16, 2021

Question 1

The time of a telephone call (in minutes) to a certain town is a continuous random variable with a probability density function defined by  for Find the probability: 
◦ 0.000001
◦ 0.000316
◦ 0.000683
◦ 0.000074

Question 2

The time to failure t, in hours, of a certain machine can often be assumed to be exponentially distributed with probability density function f(t) = ke-kt, 0 ≤ t < ∞, where k =  and a is the average amount of time that will pass before a failure occurs. Suppose the average amount of time that will pass before a failure occurs is 87 hours. What is the probability that a failure will occur in 43 hours or less?
◦ 0.4680
◦ 0.3120
◦ 0.3900
◦ 0.2925
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by jman1234 on Jun 16, 2021

lorealeza

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jman1234

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Reply 2 on: Jun 16, 2021
Gracias!

vickybb89

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Reply 3 on: Yesterday
Excellent

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