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Author Question: Use a 3D grapher to graph the function. Then estimate any relative extrema.f(x,y) = x2+ 2y2- xy2 (Read 98 times)

bobypop

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on: Jun 16, 2021

Question 1

Use a 3D grapher to graph the function. Then estimate any relative extrema.

f(x, y) = x2 + y2 - 4x - 6y
◦ Relative minimum = 0
◦ No relative extrema
◦ Relative minimum = - 13
◦ Relative maximum = 13

Question 2

Use a 3D grapher to graph the function. Then estimate any relative extrema.

f(x,y) = x2 + 2y2 - xy2
◦ Relative minimum = 0, relative maximum = 4
◦ No relative extrema
◦ Relative minima = 0, 4
◦ Relative maxima = 0, 4
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by bobypop on Jun 16, 2021

nyrave

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bobypop

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Reply 2 on: Jun 16, 2021
:D TYSM

billybob123

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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