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Author Question: 7.0 g of nitrogen is reacted with 5.0 g of hydrogen to produce ammonia according to the chemical ... (Read 51 times)

corkyiscool3328

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on: Jul 8, 2021

Question 1

52.5 mL of a solution were diluted to a volume of 6.25 L and then had a concentration of 3.16 M. What was the molarity of the initial solution?
◦ 3.16(52.5/6.25) M
◦ 3.16(6.25/52.5) M
◦ (3.16)(52.5)(6.25) M
◦ 3.16(52.5/6250) M
◦ (6.25)(3.16)/0.0525 M

Question 2

7.0 g of nitrogen is reacted with 5.0 g of hydrogen to produce ammonia according to the chemical equation shown below. Which one of the following statements is FALSE?

N2(g) + 3 H2(g) → 2 NH3(g)

◦ 3.5 g of hydrogen are left over.
◦ Hydrogen is the excess reactant.
◦ Nitrogen is the limiting reactant.
◦ The theoretical yield of ammonia is 15 g.
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by corkyiscool3328 on Jul 8, 2021

ryhom

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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corkyiscool3328

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Reply 2 on: Jul 8, 2021
Wow, this really help

parshano

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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