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Author Question: If 0.500 mol of CaCl2 is mixed with 0.200 mol Na3PO4, the maximum amount in moles of Ca3(PO4)2 that ... (Read 41 times)

nelaaney

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on: Jul 8, 2021

Question 1

If 0.500 mol of CaCl2 is mixed with 0.200 mol Na3PO4, the maximum amount in moles of Ca3(PO4)2 that can be formed is:
◦ 0.17
◦ 0.20
◦ 0.10
◦ 0.67
◦ 0.50

Question 2

If 0.500 mol of CaCl2 is mixed with 0.200 mol Na3PO4, the maximum amount in moles of Ca3(PO4)2 that can be formed is 0.10 moles.  Calculate the extent of reaction , x.
◦ 0.2
◦ 0.10
◦ 0.35
◦ 0
◦ 0.65
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by nelaaney on Jul 8, 2021

lolol

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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nelaaney

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Reply 2 on: Jul 8, 2021
YES! Correct, THANKS for helping me on my review

cpetit11

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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