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Author Question: Pure acetic acid (CH3COOH) is a liquid and is known as glacial acetic acid. Calculate the molarity ... (Read 115 times)

rachel9

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on: Jul 8, 2021
Pure acetic acid (CH3COOH) is a liquid and is known as glacial acetic acid. Calculate the molarity of a solution prepared by dissolving 10.00 mL of glacial acetic acid at 25 °C in sufficient water to give 500.0 mL of solution. The density of glacial acetic acid at 25 °C is 1.05 g mL-1.
◦ 1.26 × 103  mol L-1
◦ 21.0 mol L-1
◦ 0.0210 mol L-1
◦ 0.350 mol L-1
◦ 3.50 × 10-4  mol L-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by rachel9 on Jul 8, 2021

jointhecircus

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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rachel9

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Reply 2 on: Jul 8, 2021
YES! Correct, THANKS for helping me on my review

dreamfighter72

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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