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Author Question: A solution is prepared by mixing 50.0 mL of 0.100 mol L-1 HCl and 10.0 mL of 0.200 mol L-1 NaCl. ... (Read 50 times)

Mr3Hunna

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on: Jul 8, 2021

Question 1

A solution is 0.660 M in HNO3(aq) and 1.02 M in Ca(NO3)2(aq). What is the molarity of NO3-(aq) in the solution?
◦ 2.70 M
◦ 1.68 M
◦ 1.02 M
◦ 0.660 M
◦ 0.360 M

Question 2

A solution is prepared by mixing 50.0 mL of 0.100 mol L-1 HCl and 10.0 mL of 0.200 mol L-1 NaCl. What is the molarity of chloride ion in this solution?
◦ 0.183
◦ 8.57
◦ 3.50
◦ 0.0500
◦ 0.117
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by Mr3Hunna on Jul 8, 2021

mariahkathleeen

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Mr3Hunna

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Reply 2 on: Jul 8, 2021
Thanks for the timely response, appreciate it

carlsona147

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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