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Author Question: When dissolved in water, KOH behaves as: (Read 51 times)

ETearle

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on: Jul 8, 2021

Question 1

When 280 mL of 1.50 × 10-4 mol L-1 hydrochloric acid is added to 105 mL of 1.75 × 10-4 mol L-1 Mg(OH)2, the resulting solution will be:
◦ acidic
◦ basic
◦ neutral
◦ It is impossible to tell from the information given.

Question 2

When dissolved in water, KOH behaves as:
◦ an acid that forms K+ and OH- ions
◦ an acid that forms KO- and H+ ions
◦ a base that forms K+ and OH- ions
◦ a base that forms KO- and H+ ions
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by ETearle on Jul 8, 2021

dellikani2015

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ETearle

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Reply 2 on: Jul 8, 2021
Gracias!

phuda

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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