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Author Question: 100.0 g of nickel at 150 C was placed in 1.00 L of water at 25.0 C. The final temperature of the ... (Read 176 times)

torybrooks

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Question 1

100.0 g of Cu (specific heat = 0.385 J/g °C) at 100.0 °C is added to 140.0 mL of H2O (specific heat = 4.184 J/g °C) at 25.0 °C. What is the final temperature of the mixture?
◦ 56.3 °C
◦ 29.6 °C
◦ 62.5 °C
◦ 91.4 °C
◦ 33.7 °C

Question 2

100.0 g of nickel at 150 °C was placed in 1.00 L of water at 25.0 °C. The final temperature of the nickel-water mixture was 26.3 °C. What is the specific heat of the nickel?
◦ 0.14 J/g °C
◦ 0.13 J/g °C
◦ 0.55 J/g °C
◦ 0.44 J/g °C
◦ 0.23 J/g °C


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Marked as best answer by torybrooks on Jul 8, 2021

alexisweber49

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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torybrooks

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Reply 2 on: Jul 8, 2021
Wow, this really help


tuate

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Reply 3 on: Yesterday
:D TYSM

 

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