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Author Question: 250.0 g of hot coffee at 95.0 C are placed in a 0.2000 kg mug at 20.0 C. The specific heat of the ... (Read 56 times)

WhattoUnderstand

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on: Jul 8, 2021
250.0 g of hot coffee at 95.0 °C are placed in a 0.2000 kg mug at 20.0 °C. The specific heat of the coffee is 4.00 J/g °C, while that of the mug is 0.80 J/g °C. Assuming no heat is lost to the surroundings, what is the final temperature of the system: mug + coffee?
◦ 61.7 °C
◦ 117 °C
◦ 76.0 °C
◦ 57.5 °C
◦ 84.7 °C
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by WhattoUnderstand on Jul 8, 2021

softEldritch

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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WhattoUnderstand

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Reply 2 on: Jul 8, 2021
:D TYSM

Missbam101

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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