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Author Question: Given that fH [Ag2S(s)] = -32.6 kJ/mole, what is the enthalpy change for the precipitation of ... (Read 13 times)

rlane42

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Given that Δf [Ag2S(s)] = -32.6 kJ/mole, what is the enthalpy change for the precipitation of argentite, Ag2S(s)?

Δf [Ag+(aq)] = +105.6 kJ/mol
Δf [S2-(aq)] = +33.05 kJ/mol

◦ -276.9 kJ/mol
◦ -106.1 kJ/mol
◦ +171.2 kJ/mol
◦ +106.1 kJ/mol
◦ +138.7 kJ/mol


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Marked as best answer by rlane42 on Jul 8, 2021

jazzlynnnnn

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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rlane42

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Reply 2 on: Jul 8, 2021
:D TYSM


chjcharjto14

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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