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Author Question: Given the following reactions: 2 NOCl(g) 2 NO(g) + Cl2(g) rH = +75.56 kJ/mol 2 NO(g) + O2(g) 2 ... (Read 114 times)

809779

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Given the following reactions:

2 NOCl(g) → 2 NO(g) + Cl2(g)  Δr =  +75.56 kJ/mol
2 NO(g) + O2(g) → 2 NO2(g)  Δr =  -113.05 kJ/mol
2 NO2(g) → N2O4(g) Δr =  -58.03 kJ/mol

Compute Δr of N2O4(g) + Cl2(g) → 2 NOCl(g) + O2(g) in kJ/mol.
◦ +246.65 kJ/mol
◦ -95.52 kJ/mol
◦ -246.65 kJ/mol
◦ +95.52 kJ/mol
◦ +130.58 kJ/mol


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Marked as best answer by 809779 on Jul 8, 2021

olivia_paige29

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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809779

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Reply 2 on: Jul 8, 2021
Excellent


sarah_brady415

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Reply 3 on: Yesterday
Gracias!

 

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