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Author Question: Given the following reactions: 2 NOCl(g) 2 NO(g) + Cl2(g) rH = +75.56 kJ/mol 2 NO(g) + O2(g) 2 ... (Read 111 times)

809779

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Given the following reactions:

2 NOCl(g) → 2 NO(g) + Cl2(g)  Δr =  +75.56 kJ/mol
2 NO(g) + O2(g) → 2 NO2(g)  Δr =  -113.05 kJ/mol
2 NO2(g) → N2O4(g) Δr =  -58.03 kJ/mol

Compute Δr of N2O4(g) + Cl2(g) → 2 NOCl(g) + O2(g) in kJ/mol.
◦ +246.65 kJ/mol
◦ -95.52 kJ/mol
◦ -246.65 kJ/mol
◦ +95.52 kJ/mol
◦ +130.58 kJ/mol


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Marked as best answer by 809779 on Jul 8, 2021

olivia_paige29

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809779

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Reply 2 on: Jul 8, 2021
Wow, this really help


diana chang

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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