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Author Question: Given the heat of formation of the following compounds: CO2(g) fH = -393.5 kJ/mol H2O(l) fH = -285.9 ... (Read 41 times)

silviawilliams41

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on: Jul 8, 2021
Given the heat of formation of the following compounds:
CO2(g)  ΔfH° = -393.5 kJ/mol
H2O(l)  ΔfH° = -285.9 kJ/mol
CH3OH(l)  ΔfH° = -238.6 kJ/mol

What is the value of ΔrH° for the reaction:
CH3OH(l) + 3/2 O2(g) → CO2(g) + 2 H2O(l)

◦ -440.8 kJ/mol
◦ -416.9 kJ/mol
◦ -1203.9 kJ/mol
◦ -346.2 kJ/mol
◦ -726.7 kJ/mol
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by silviawilliams41 on Jul 8, 2021

jesse.fleming

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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silviawilliams41

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Reply 2 on: Jul 8, 2021
Thanks for the timely response, appreciate it

hramirez205

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Reply 3 on: Yesterday
:D TYSM

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