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Author Question: Given the bond enthalpies NH (389), ClCl (243), NCl (201), and HCl (431) in kJ/mol, compute H in ... (Read 114 times)

wrbasek0

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Question 1

Given the bond enthalpies ICl (209), HH (435), HI (297), and HCl (431) in kJ/mol, compute Δ in kJ/mol for: ICl3(g) + 2 H2(g) → HI(g) + 3 HCl(g).
◦ +264 kJ/mol
◦ -84 kJ/mol
◦ -93 kJ/mol
◦ -523 kJ/mol
◦ +84 kJ/mol

Question 2

Given the bond enthalpies NH (389), ClCl (243), NCl (201), and HCl (431) in kJ/mol, compute Δ in kJ/mol for: NH3(g) + Cl2(g) → NH2Cl + HCl(g).
◦ -393 kJ/mol
◦ -1100 kJ/mol
◦ +71 kJ/mol
◦ +393 kJ/mol
◦ 0 kJ/mol


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Marked as best answer by wrbasek0 on Jul 8, 2021

kkenney

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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wrbasek0

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Reply 2 on: Jul 8, 2021
Excellent


phuda

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Reply 3 on: Yesterday
Wow, this really help

 

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