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Author Question: If 34 g of a solid with a molar mass = 174 g/mol requires 21.3 kJ to melt it, what is the molar heat ... (Read 43 times)

EY67

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Question 1

How much heat would be released by the condensation of 5.40 g of steam at 100 °C and the subsequent cooling of the water to 25 °C? [ΔvapH = 40.7 kJ/mol at 100 °C; Cp for H2O(l) is 4.18 J g-1°C-1]
◦ 12.2 kJ
◦ 12.8 kJ
◦ 13.9 kJ
◦ 18.3 kJ
◦ 23.7 kJ

Question 2

If 34 g of a solid with a molar mass = 174 g/mol requires 21.3 kJ to melt it, what is the molar heat of fusion in kJ/mol?
◦ (21.3)(174)(34) kJ/mol
◦ (21.3/174)(34) kJ/mol
◦ (21.3/174)/34 kJ/mol
◦ (21.3)(174/34) kJ/mol
◦ (34/21.3)(174) kJ/mol


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Marked as best answer by EY67 on Jul 8, 2021

aburgess

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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EY67

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Reply 2 on: Jul 8, 2021
:D TYSM


jojobee318

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Reply 3 on: Yesterday
Wow, this really help

 

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