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Author Question: Determine the pH of 263 ml of an aqueous solution which has [NH4I] = 0.300 M. Kb = 1.74 10-5 for NH3(aq). (Read 67 times)

Capo

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on: Jul 8, 2021

Question 1

Determine the ammonia concentration of an aqueous solution that has a pH of 11.00. The equation for the dissociation of NH3 (Kb = 1.8 × 10-5) is below:



◦ 3.0 mol L-1
◦ 0.056 mol L-1
◦ 1.8 × 10-2 mol L-1
◦ 1.0 × 10-3 mol L-1

Question 2

Determine the pH of 263 ml of an aqueous solution which has [NH4I] = 0.300 M. Kb = 1.74 × 10-5 for NH3(aq).
◦ 2.6
◦ 11.4
◦ 4.9
◦ 9.1
◦ 4.6
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by Capo on Jul 8, 2021

nikmaaacs

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Capo

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Reply 2 on: Jul 8, 2021
:D TYSM

amit

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Reply 3 on: Yesterday
Gracias!

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