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Author Question: Determine Ecell for the reaction: MnO4-(aq) + 8 H+(aq) + 5 Fe2+(aq) Mn2+(aq) + 4 H2O(l) + 5 ... (Read 17 times)

Zoey63294

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Determine cell for the reaction: MnO4-(aq) + 8 H+(aq) + 5 Fe2+(aq) → Mn2+(aq) + 4 H2O(l) + 5 Fe3+(aq). The half reactions are:

Fe3+(aq) + e-→ Fe2+(aq) = +0.771 V
MnO4-(aq) + 8 H+(aq) + 5 e-→ Mn2+(aq) + 4 H2O(l) = 1.507 V

◦ -2.34 V
◦ -2.28 V
◦ 2.28 V
◦ -0.74 V
◦ 0.74 V


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Marked as best answer by Zoey63294 on Jul 8, 2021

wtf444

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Zoey63294

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Reply 2 on: Jul 8, 2021
Wow, this really help


EAN94

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Reply 3 on: Yesterday
Excellent

 

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