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Author Question: For a particular first-order reaction, it takes 24 minutes for the concentration of the reactant to ... (Read 56 times)

tiara099

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on: Jul 8, 2021

Question 1

For 2 NO + O2→ 2 NO2, initial rate data are:  

[NO]0 (in M) 0.010 0.010 0.030
[O2]0 (in M) 0.010 0.020 0.020
rate (mM/sec) 2.5 5.0 45.0

The rate law is Rate = k[NO][O2]y:
◦ x = 1, y = 2
◦ x = 2, y = 1
◦ x = 1, y = 1
◦ x = 2, y = 2
◦ x = 0, y = 2

Question 2

For a particular first-order reaction, it takes 24 minutes for the concentration of the reactant to decrease to 25% of its initial value. What is the value for rate constant (in s-1) for the reaction?
◦ 2.0 × 10-4 s-1
◦ 9.6 × 10-4 s-1
◦ 1.2 × 10-2 s-1
◦ 5.8 × 10-2 s-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by tiara099 on Jul 8, 2021

trampas

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tiara099

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Reply 2 on: Jul 8, 2021
Thanks for the timely response, appreciate it

adf223

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Reply 3 on: Yesterday
Wow, this really help

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