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Author Question: Why is rate = k[HgCl2] 2[C2O42-] not the rate law for the following mechanism? 2 HgCl2 + C2O42- 2 ... (Read 43 times)

karen

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on: Jul 8, 2021
Why is rate = k[HgCl2] 2[C2O42-] not the rate law for the following mechanism?

2 HgCl2 + C2O42-→ 2 Cl- + 2 CO2 + Hg2Cl2 (overall reaction)
HgCl2 + C2O42- HgCl2C2O42- (fast)
HgCl2C2O42- + C2O42-→ Hg + 2 C2O4Cl2- (slow)
Hg + HgCl2→ Hg2Cl2 (fast)
2 C2O4Cl2-→ C2O42- + 2 Cl- + 2 CO2 (fast)

◦ The rate law is not based on the slow step of the proposed mechanism.
◦ The steps do not add to the overall reaction.
◦ The rate law does not agree with the overall reaction.
◦ The exponents of HgCl2 and C2O42- are not equal.
◦ The first step is not the slow step.
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by karen on Jul 8, 2021

brittanywood

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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karen

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Reply 2 on: Jul 8, 2021
YES! Correct, THANKS for helping me on my review

anyusername12131

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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