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Author Question: Which molecule is optically active? (Read 258 times)

CBme

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on: Jul 8, 2021

Question 1

When the equation for the oxidation of glucose is balanced, the coefficients are: ________.

C6H12O6 + O2→ CO2 + H2O

◦ 2, 6, 12, 12
◦ 1, 3, 6, 6
◦ 1, 6, 6, 6
◦ 1, 9, 6, 12
◦ 4, 2, 4, 2

Question 2

Which molecule is optically active?
◦ 2-chlorobutane
◦ 1-chlorobutane
◦ trans-propene
◦ cis-propene
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by CBme on Jul 8, 2021

firehawk60

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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CBme

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Reply 2 on: Jul 8, 2021
YES! Correct, THANKS for helping me on my review

miss.ashley

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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