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Author Question: A 25-kg mass is attached to a spring that hangs vertically and is stretched 1 m from the equilibrium ... (Read 609 times)

APUS57

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on: Dec 18, 2021
A 25-kg mass is attached to a spring that hangs vertically and is stretched 1 m from the equilibrium position of the spring. Assume a linear spring with F(x) = kx. How much work is required to stretch the spring and lower the mass 1.5 m? Round to four decimal places when appropriate.
◦ 459.375 J
◦ 643.125 J
◦ 91.875 J
◦ 1010.625 J
Calculus: Early Transcendentals ¦ Briggs, Cochran, Gillett, Schulz ¦ 3rd Edition
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Marked as best answer by APUS57 on Dec 18, 2021

heinisk01

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Reply #1 on: Dec 18, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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APUS57

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Reply 2 on: Dec 18, 2021
Excellent

phuda

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Reply 3 on: Yesterday
Wow, this really help

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