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Author Question: Which of the following best explains if NaNH2 is a suitable reagent to deprotonate the compound shown below? (Read 3119 times)

lrhoads

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on: Feb 17, 2022
Which of the following best explains if NaNH2 is a suitable reagent to deprotonate the compound shown below?



◦ yes, the resulting conjugate base would have delocalization of charge over two oxygen atoms, whereas NaNH2 has a localized negative charge.
◦ no, NaNH2 produces NH3 when protonated which then will leave the reaction mixture
◦ no, there are no acidic protons attached to the oxygen atoms
◦ yes, as NaNH2 has only two hydrogen atoms attached to the nitrogen atom, and the compound has eight total hydrogen atoms
◦ no, the resulting conjugate base would have a localized negative on a carbon atom where NaNH2 has a negative on the more electronegative nitrogen atom
Organic Chemistry ¦ Klein ¦ 4th Edition
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Marked as best answer by lrhoads on Feb 17, 2022

khudija

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Reply #1 on: Feb 17, 2022
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kk38747

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Reply #2 on: Sep 8, 2023
thank you


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